| Subject: | anonymous coercions (via declare_coercion) ignore passed coercion maps if not in a Type::Library |
I'm trying to construct an anonymous coercion using Type::Utils::declare_coercion in a class definition (not a type library).
e.g.,
my $foo = declare_coercion to_type ArrayRef, from Any, via { [$_] };
However, it looks like declare_coercion only pays attention to the "type, coderef" arguments if it is called from a type library. Attached is some test code, which results in the following output:
ok 1 - Type library, coercion mapped
not ok 2 - Not in Type library, coercion mapped
# Failed test 'Not in Type library, coercion mapped'
# at coerce2 line 28.
# got: undef
# expected: 'Any'
1..2
Bug or Feature? The documentation for "declare" explicitly notes that it can be used outside of a type library. While that for "declare_coercion" doesn't, it seems a reasonable assumption that it would.
Thanks,
Diab
| Subject: | anonymous_coercion.t |
#! perl
use Test::More;
{
package lib;
use Test::More;
use Type::Library -base;
use Types::Standard -all;
use Type::Utils -all;
my $foo = declare_coercion to_type ArrayRef, from Any, via { [$_] };
is( $foo->type_coercion_map->[0], 'Any', "Type library, coercion mapped" );
}
{
package notlib;
use Test::More;
use Types::Standard -all;
use Type::Utils -all;
my $foo = declare_coercion to_type ArrayRef, from Any, via { [$_] };
is( $foo->type_coercion_map->[0], 'Any',
"Not in Type library, coercion mapped" );
}
done_testing;