Subject: | downfloaters aren't recognised by C3 |
Date: | Wed, 19 Sep 2007 11:12:13 +0200 |
To: | bug-Games-Tournament-Swiss [...] rt.cpan.org |
From: | Christian Bartolomaeus <bartolin [...] gmx.de> |
Hi,
I stumbled about the following situation:
Pairingtable:
Round 5 Pairing Groups
-------------------------------------------------------------------------
Place No Opponents Roles Float Score
1
8 18,5,3,1 BWBW D 3.5
2
1 11,10,6,8 WBWB U 3
3-9
2 12,7,9,5 BWBW 2.5
4 14,9,7,17 BWBW 2.5
5 15,8,13,2 WBWB 2.5
7 17,2,4,9 WBWB 2.5
9 19,4,2,7 WBWW 2.5
16 6,19,11,10 WBWB 2.5
17 7,14,18,4 BWBB d 2.5
10-14
3 13,6,8,11 WBWB u 2
6 16,3,1,15 BWBW 2
11 1,12,16,3 BWBW 2
13 3,18,5,19 BWBW 2
15 5,20,10,6 BWWB 2
15-16
10 20,1,15,16 BWBW 1.5
20 10,15,14,12 WBBW D 1.5
17-19
12 2,11,19,20 WBWB dU 1
18 8,13,17,14 WBWW u 1
19 9,16,12,13 BWBB u 1
20
14 4,17,20,18 WBWB 0
Now 1 is moved down to Bracket 2. There is no possible pairing, since
1 and 8 played in round 4 already. Therefore 1 and 8 are moved down to
Bracket 3.
For some reason, now Bracket 3 is recognised as 'heterogenous' by
Bracket.pm (sub hetero), but the downfloaters aren't recognised in
Bracket.pm (sub p). Therefore p is calculated wrongly (it should be
2) and S1 and S2 are wrong as well:
Show quoted text
> Round 5: 8 (3.5), 1 (3), 2 4 5 7 9 16 17 (2.5), 3 6 11 13 15 (2), 10 20 (1.5), 12 18 19 (1), 14 (0),
> Next, Bracket 1: 8
> C1, Bracket 1. Floating 8 Down, [1] 8 => [2] 8 1
>
> Next, Bracket 2: 8 1
> C1, NOK. 8 1
> C12, Heterogenous group 1 now homogeneous
> C14, Bracket 2, now p=0
> Moving down all Bracket 2, to 3. Bracket 2: 8 1 => Bracket 3: 1 8 2 4 5 7 9 16 17
> Next, Bracket 3: 1 8 2 4 5 7 9 16 17
> C1, B1,2 test: ok, no unpairables
> C2, x=0
> C3, p=4 Heterogeneous.
> C4, S1 & S2: 8 1 2 4 & 5 7 9 16 17
Best regards
Christian
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